• FizzyOrange@programming.devBanned from community
    33·
    3 months ago

    this is about non-generic code in generic header.

    (a << 16) | b is about the most generic code you can get. How is that remotely RISC-V specific?

    • zygo_histo_morpheus@programming.dev
      11·
      3 months ago

      Making a u32 pointer from two u16’s isn’t a generic operation because it has to make assumptions about how the pointers work endianess

      Edit: Actually, I’m wrong, didn’t think this through properly. See the replies

          • FizzyOrange@programming.devBanned from community
            3·
            3 months ago

            Nw. You’re also wrong about endianness. This function would be written exactly the same irrespective of endianness:

            uint32_t u16_high_low_to_u32(uint16_t high, uint16_t low) {
  return (high << 16) | low;
}

            That is endian agnostic.