• zygo_histo_morpheus@programming.dev
    11·
    3 months ago

    Making a u32 pointer from two u16’s isn’t a generic operation because it has to make assumptions about how the pointers work endianess

    Edit: Actually, I’m wrong, didn’t think this through properly. See the replies

        • FizzyOrange@programming.devBanned from community
          3·
          3 months ago

          Nw. You’re also wrong about endianness. This function would be written exactly the same irrespective of endianness:

          uint32_t u16_high_low_to_u32(uint16_t high, uint16_t low) {
  return (high << 16) | low;
}

          That is endian agnostic.